$ scope中的角JS执行函数$ timer接收到TypeError [英] Angular JS executing function $timer within $scope receives TypeError

问题描述

为什么在Angular JS中使用$timeout时，内部函数如下所示，效果很好.

Why is that when using $timeout in Angular JS that is inside function like the following, works fine.

var mytimeout = $timeout(function(){
    console.log("MyTimeout Executed");
},2000);
mytimeout.then(
    function() {
        console.log( "mytimeout resolved!", Date.now() );
    },
    function() {
        console.log( "mytimeout rejected!", Date.now() );
    }
);

但是当我将$timer与$scope内部的函数一起使用时，它将无法正常工作，像这样:

but when I use $timer with a function inside $scope it does not work, like this:

$scope.myFunction = function(){
   console.log("MyTimeout Executed");
}; 

var mytimeout = $timeout($scope.myFunction(),2000);
mytimeout.then(
    function() {
        console.log( "mytimeout resolved!", Date.now() );
    },
    function() {
        console.log( "mytimeout rejected!", Date.now() );
    }
);

并收到此错误:

TypeError: undefined is not a function
    at http://0.0.0.0:3000/assets/angular.js?body=1:14015:28
    at completeOutstandingRequest (http://0.0.0.0:3000/assets/angular.js?body=1:4301:10)
    at http://0.0.0.0:3000/assets/angular.js?body=1:4602:7 angular.js?body=1:9779
(anonymous function) angular.js?body=1:9779
(anonymous function) angular.js?body=1:7217
(anonymous function) angular.js?body=1:14018
completeOutstandingRequest angular.js?body=1:4301
(anonymous function) angular.js?body=1:4602

推荐答案

var mytimeout = $timeout($scope.myFunction(),2000);

这是您的问题.从myFunction()移除().您需要传递函数引用，而不是调用函数并获取结果(在本例中为undefined)，然后将 that 传递给$ timeout.

This is your problem. Remove the () from the myFunction(). You need to pass a function reference, not call the function and take the result (which in this case would be undefined) and then pass that to $timeout.

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