在Anylogic中设置下车区 [英] Setting drop-off block in anylogic

问题描述

如何设置下车区以在一个火车站卸载一定比例的人，而在下一个火车站卸载不同比例的人?

How can I set the drop-off block to unload a certain percentage of people at one train station and a different percentage at the next train station?

推荐答案

您可以通过执行container.contents().size()

让我们想象一下，您想在第一个下降50％，在第二个下降10％.

Let's imagine you want to dropoff 50% in the first and 10% in the second.

在第一个下达中，假设您要下达50％，则可以选择下达选项给定数量，如果可用"，并将数量设置为(int)round((container.contents().size())*0.5)
当然，如果您想降低30％，则可以将0.5更改为0.3.

In the first dropoff, assuming that you want to dropoff 50% you can choose the option dropoff "given quantity if available" and set the quantity as (int)round((container.contents().size())*0.5)
Of course you can change 0.5 to 0.3 if you want to dropoff 30%.

在下一个下降中，您希望下降初始人口的10％(但仅剩50％，因此您要下降当前人口的20％ (int)round((container.contents().size())*0.2)

In the next dropoff you want to dropoff 10% of the initial population (but only 50% is remaining, so you want to dropoff 20% of the current population (int)round((container.contents().size())*0.2)

让我们想象一下，您的初始人口为100，而您想让第一位乘客减少50％，第二位乘客减少10％(第一位乘客50位，第二位乘客10位) (int)round((container.contents().size())*0.5)会降落这50名乘客，因此您只剩下50名乘客，第二秒钟您想降落10名乘客. 10，是50的20％...这就是为什么我在第二个下降项中使用0.2

Let's imagine that you have 100 in the initial population and you want to dropoff 50% on the first and 10% on the second (50 passengers in the first and 10 passengers in the second) (int)round((container.contents().size())*0.5) will dropoff those 50 passengers, so you will have only 50 passengers left and on the second you want to dropoff 10 passengers. 10, is 20% of 50... that's why I use 0.2 in the second dropoff

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