如何摆脱这种“做时循环"? [英] How to get out this Do-While loop?

问题描述

我有这个基本的Arduino代码，我想有 2个选项退出此Do-While循环. 我简化了原始代码以突出显示真正的问题:当-不能识别OR ||"时，退出循环的条件

I've this basic Arduino code, and I want to have 2 options to exit this Do-While loop. I simplified my original code to highlight the real problem: the Do-While doesn't recognize the OR || condition to exit the loop

在这段代码中，我从两个等于零的整数变量开始，并且一旦它们进入Do-While，它们都将被设置为等于2，以便它们可以立即退出Do-While在第一次迭代中.

In this code I'm starting with two integer variables that are equal to zero and as soon as they enter the Do-While, they'will be setted equal to 2 both, so that they can immediately exit the Do-While in the first iteration.

这是我的代码:

int fin = 0;
int ending = 0;
int counter = 0;


void setup() {

  Serial.begin(9600);

}; //void setup



void loop ()  {

  do  {

      Serial.println("We are IN Do-While #1");
      ending = 2;
      //fin = 2;

  } while ((ending < 1) || (fin < 1)); //I have just one condition for exit the Do-While ending = 1


Serial.println("We are OUT Do-While #1");
delay(3000);


  do {

    counter++;
  } while(counter<=100);

  Serial.println("We are OUT Do-While #2");
delay(3000);

  }

我的问题是我没有设置 fin = 2 ，因为我想测试OR条件是否正常.

My problem is that I'm not setting fin = 2, because I want to test if the OR condition is working.

但是，除非它们都等于2，否则似乎无法退出Do-While.这对我来说很奇怪，因为在这种特殊情况下，OR条件允许使用双精度选项退出Do-While.这些选项是:

But it seems that it can't exit the Do-While unless they're both equal to 2. This is strange to me because the OR condition allows to exit the Do-While with a double options, in this particular case these options are:

结尾< 1 或(替代选项).. fin< 1

ending<1 OR (the alternative option).. fin<1

另外，如果我更改(代码的其余部分相同)，则使用AND的while条件的行为将与我想要的一样:这样，我有两种方法可以退出Do-While循环. 像这样:

Additionally if I change (the rest of the code is the same) the while condition with an AND it behave like I want: so that I have two ways to exit the Do-While loop. Like this:

} while ((ending < 1) && (fin < 1));

但不是在AND条件下，我必须同时匹配 ending> = 1 和AND(同时) fin> = 1 的两个条件才能退出循环?

But wouldn't be that in an AND condition I must match BOTH condition of ending >= 1 AND (at the same time) fin >= 1 to exit the loop?

为什么会这样? 而我该如何解决呢?

Why is this happening? and How can I solve this?

推荐答案

但是，除非它们都等于2，否则似乎无法退出Do-While.这对我来说很奇怪，因为在这种特殊情况下，OR条件允许使用双精度选项退出Do-While.这些选项是:

But it seems that it can't exit the Do-While unless they're both equal to 2. This is strange to me because the OR condition allows to exit the Do-While with a double options, in this particular case these options are:

实际上，情况恰恰相反.

Actually, it's the opposite.

循环有两个选项继续前进.

我确定您的意思是&&，而不是||.

I'm sure you meant &&, not ||.

但是不是在AND条件下我必须同时匹配> = 1 AND(同时)fin> = 1的两个条件吗?

But wouldn't be that in an AND condition I must match BOTH condition of ending >= 1 AND (at the same time) fin >= 1?

是的，继续.

这意味着，您只需不匹配其中一个 即可停止

Which means, you only need to not match one of them, to stop.

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