遍历* args? [英] Iterate over *args?

问题描述

我有一个正在处理的脚本，需要在其中接受多个参数，然后遍历它们以执行操作.我开始定义函数并使用* args.到目前为止，我有类似下面的内容:

I have a script I'm working on where I need to accept multiple arguments and then iterate over them to perform actions. I started down the path of defining a function and using *args. So far I have something like below:

def userInput(ItemA, ItemB, *args):
    THIS = ItemA
    THAT = ItemB
    MORE = *args

我想做的是将* args中的参数放入一个可以迭代的列表中.我在StackOverflow和Google上都看过其他问题，但似乎找不到我想要做的答案.预先感谢您的帮助.

What I'm trying to do is get the arguments from *args into a list that I can iterate over. I've looked at other questions on StackOverflow as well as on Google but I can't seem to find an answer to what I want to do. Thanks in advance for the help.

推荐答案

获得您的精确度语法:

def userInput(ItemA, ItemB, *args):
    THIS = ItemA
    THAT = ItemB
    MORE = args

    print THIS,THAT,MORE


userInput('this','that','more1','more2','more3')

在分配给MORE的操作中，删除了args前面的*.然后，MORE成为userInput

You remove the * in front of args in the assignment to MORE. Then MORE becomes a tuple with the variable length contents of args in the signature of userInput

输出:

this that ('more1', 'more2', 'more3')

正如其他人所述，将args视为可迭代的对象更为常见:

As others have stated, it is more usual to treat args as an iterable:

def userInput(ItemA, ItemB, *args):    
    lst=[]
    lst.append(ItemA)
    lst.append(ItemB)
    for arg in args:
        lst.append(arg)

    print ' '.join(lst)

userInput('this','that','more1','more2','more3') 

输出:

this that more1 more2 more3

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