模板函数采用std :: vector或std :: array [英] Template function taking a std::vector or std::array

问题描述

我有一个函数，当前可以接受2个向量，这些向量可以包含任何简单的旧数据...

I have a function that currently accepts 2 vectors that can contain any plain old data ...

template <class T>
void addData(const vector<T>& yData, vector<T> xData)
{ .. }

问题:

• 考虑到这些容器采用不同数量的模板参数，是否可以将其修改为两个std::array或两个std::vector甚至是它们的组合?

• Would it be possible to modify it to take two std::array or two std::vector, or even a combination thereof, given that these containers take a different number of template arguments?

推荐答案

为什么不只使用它，它可以与任何使用随机访问迭代器的容器一起使用，包括普通的旧数组.如果可以使用迭代代替索引，那么也可以消除随机访问的要求.

Why not just use this, which works with any container using random-access iterators, including plain old arrays. If you can use iteration instead of indexing, you can do away with the random-access requirement as well.

template <typename Cnt1, typename Cnt2>
void addData(const Cnt1& yData, Cnt2 xData) // is pass-by-value intended?
{
    using std::begin;
    using std::end;
    typedef decltype(*begin(yData)) T;
    const auto sizeY = end(yData) - begin(yData);
    const auto sizeX = end(xData) - begin(xData);
    // ...
}

C ++ 03版本(不支持普通的旧数组):

C++03 version (doesn't support plain old arrays):

template <typename Cnt1, typename Cnt2>
void addData(const Cnt1& yData, Cnt2 xData) // is pass-by-value intended?
{
    typedef Cnt1::value_type T;
    const size_t sizeY = yData.end() - yData.begin();
    const size_t sizeX = xData.end() - xData.begin();
    // ...
}

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