如何用该代码点将十六进制字符串转换为字符? [英] How to convert hexadecimal string to character with that code point?

问题描述

我有字符串x = '0x32'，想将其转换为y = '\x32'.
请注意len(x) == 4和len(y) == 1.

I have the string x = '0x32' and would like to turn it into y = '\x32'.
Note that len(x) == 4 and len(y) == 1.

我尝试使用z = x.replace("0", "\\")，但这会导致z = '\\x32'和len(z) == 4.我该如何实现?

I've tried to use z = x.replace("0", "\\"), but that causes z = '\\x32' and len(z) == 4. How can I achieve this?

推荐答案

您不必那么费劲:您可以使用int(..,16)来解析形式为0x...的十六进制字符串.接下来，您只需使用chr(..)将该数字转换为具有Unicode的字符(并且如果代码小于128 ASCII):

You do not have to make it that hard: you can use int(..,16) to parse a hex string of the form 0x.... Next you simply use chr(..) to convert that number into a character with that Unicode (and in case the code is less than 128 ASCII) code:

y = chr(int(x,16))

结果是:

>>> chr(int(x,16))
'2'

但是\x32等于'2'(您可以在ASCII表中查找它):

But \x32 is equal to '2' (you can look it up in the ASCII table):

>>> chr(int(x,16)) == '\x32'
True

和:

>>> len(chr(int(x,16)))
1

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