5个逗号分隔的电子邮件ID的正则表达式 [英] Regular expression for 5 comma separated email id

问题描述

我试图用一个正则表达式验证5个逗号分隔的电子邮件ID. 我在下面使用正则表达式

I trying to validate 5 comma separated email id in one regular expression. I currntly using below regex

^([\w+-.%]+@[\w-.]+\.[A-Za-z]{2,4},?)+$

这对于一个电子邮件ID有效.

This is valid for one email id.

我想知道如何实现相同的目标，对同一目标的任何小投入也将不胜感激.

I would like to know how I can achieve the same, any small inputs on the same is also greatly appreciated.

谢谢.

推荐答案

首先，修复模式:-在字符类的两个字符之间形成一个范围.因此，您的正则表达式的电子邮件部分应为[-\w+.%]+@[\w-.]+\.[A-Za-z]{2,4}(请注意-在第一个字符类中的位置，在第二个字符类中，可以将其放在速记字符类\w和下一个字符之间)

First of all, fix the pattern: - in between two chars inside a character class forms a range. So, the email part of your regex should be [-\w+.%]+@[\w-.]+\.[A-Za-z]{2,4} (note the position of - in the first character class, in the second, it is OK to put it between a shorthand character class \w and the next char).

接下来，要匹配1到5个逗号分隔的电子邮件，您需要匹配第一个，然后匹配0到4个电子邮件.并在模式周围添加锚点，以确保模式与整个字符串匹配:

Next, to match 1 to 5 comma-separated emails, you need to match the first one, and then match 0 to 4 emails. And add anchors around the pattern to make sure the pattern matches the whole string:

^[-\w+.%]+@[\w-.]+\.[A-Za-z]{2,4}(?:,[-\w+.%]+@[\w-.]+\.[A-Za-z]{2,4}){0,4}$

基本上是^<EMAIL>(?:,<EMAIL>){0,4}$:

• ^-字符串开头
• <EMAIL>-您的电子邮件格式
• (?:-一个非捕获组的开始，该组充当一系列模式的容器:
  • ,-逗号
  • <EMAIL>-您的电子邮件格式
  • ^ - start of string
  • <EMAIL> - an email pattern of yours
  • (?: - start of a non-capturing group acting as a container for a sequence of patterns:
    • , - a comma
    • <EMAIL> - an email pattern of yours

    另一个想法是使用,进行拆分，然后进行验证:

    Another idea is to split with , and then validate:

    var s = "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]";
    var re = /^[-\w+.%]+@[\w-.]+\.[A-Za-z]{2,4}$/;
    var items = s.split(",");
    if (items.length <= 5 && items.filter(function(x) { return re.test(x); }).length === items.length ) {
       console.log("VALID => ", items);
    } else {
       console.log("INVALID!");
    }

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