如何将通用参数传递到局部视图 [英] How to pass generic parameter to partial view

问题描述

可能重复:
泛型部分视图:如何设置泛型类作为模型?

Possible Duplicate:
Generic partial view: how to set a generic class as model?

我正在尝试使用泛型类型构建通用功能，但遇到了以下情况.

I am trying to build common functionality using generic types but got stuck with below scenario.

查看模型

public class DeleteForm<T>  
{
    public LogInfo Ticket { get; set; }
    public string Id { get; set; }

    public DeleteForm() {
      Ticket = new LogInfo();
    }

    public DeleteForm(T viewModel) : this() {
      ViewModel = viewModel;
    }

    public T ViewModel { get; set; }
}

控制器

public ActionResult Index(string name)
{
   return View("index", new DeleteForm<List<Users>>(new List<Users>());
}

列表屏幕

@model DeleteForm<List<Users>>
//gridview displays list of users
@Html.Partial("revisionwindow", Model)

局部视图

@model DeleteForm<T> <---Its not working

@Html.EditorFor(o=>o.Ticket)
@Html.EditorFor(o=>o.Id)

推荐答案

如果要传递模型进行查看，则必须使用强类型(特定类型)的模型. 因此SomeClass<T>类型将不起作用.可以使用基类代替泛型类型来填充 您的要求.我的意思是: 查看模型

If you pass a model to view, it has to be strongly-typed (particular type). So SomeClass<T> type won't work. Instead of generic type a base class could fill your requirements. What I mean is: View Model

public abstract class Form
{
    public Form()
    {
        Ticket = new LogInfo();
    }
    public LogInfo Ticket {get; set;}
    public int Id {get; set;}
}
public class DeleteUsersForm: Form
{
    public DeleteUsersForm(IEnumerable<Users> users):base()
    {
        this.ViewModel = users;
    }

    public IEnumerable<Users> ViewModel {get; set;}
}

控制器

public ActionResult Index(string name)
{
    return View(new DeleteUsersForm(new List<Users>()));
}

列表屏幕

@model DeleteUsersForm
//displays list
@Html.Partial("revisionwindow", Model)

局部视图

@model Form

@Html.EditorFor(o=>o.Ticket)
@Html.EditorFor(o=>o.Id)

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