如何将参数传递给 Django 通用视图 [英] How to pass parameters to django generic views

问题描述

我想将一个数字传递给我的通用视图 (DetailView) 以获取一个对象 这是我的代码

I would like to pass a number to my generic view (DetailView) to get one object Here is my code

网址模式

(r'^newreportview/(?P<number>w+)/$', NewReportView.as_view()),  

查看类

class NewReportView(DetailView):
    template_name = "report/newreportview.html"
    context_object_name = "newreportview"
    def get_queryset(self):
        task= get_object_or_404(MyTask,applicationnnumber=self.args[0])
        return task

我想这行有问题

name = get_object_or_404(MyTask,applicationnnumber=self.args[0])

错误信息:

Exception Type: IndexError
Exception Value:
tuple index out of range

我应该如何将数字"传递给这个通用视图并使用这个数字"获取 Mytask 对象?

How should I pass 'number' to this generic view and get a Mytask object with this 'number'?

谢谢

推荐答案

您错过了通用视图的全部要点.对于一个简单的 DetailView - 它是单个对象的视图 - 您只需在类中定义 model 和 slug 属性:

You have missed the entire point of generic views. For a simple DetailView - which is a view of a single object - you just define the model and slug attributes in the class:

(r'^newreportview/(d+)/$', NewReportView.as_view()),  

class NewReportView(DetailView):
    template_name = "report/newreportview.html"
    model = MyTask
    slug = 'applicationnnumber'

(您也可以很容易地在 URL 定义中将这三个作为参数传递，因此根本不需要创建子类.)

(You could also just as easily have passed those three as parameters in the URL definition, so no need to make a subclass at all.)

您没有获得 self.args 值的原因是您将参数作为 kwarg 传递，而不是 arg.所以 self.kwargs['number'] 会起作用，就像我在此处显示的修改后的 URL 一样.

The reason why you were getting no values for self.args is that you had passed your parameter as a kwarg, not an arg. So self.kwargs['number'] would have worked, as would the revised URL I've shown here.

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