如何使用循环绘制正方形(int 10h)? [英] How to draw a square (int 10h) using loops?

问题描述

您可以使用设置为10h的21h的新行吗?
如果没有，那么如何通过8086为10h设置一条新线? 我想做的是使用类似于正方形的循环.

Can you use new line that has 21h on a setting of 10h?
if not then how would it be possible to set a new line for 10h via 8086? What im trying to do is to use loops that would resemble a square.

org  100h

mov ah, 0   ; set display mode function.
mov al, 13h ; mode 13h = 320x200 pixels, 256 colors.
int 10h     ; set it!

mov cx, 10
mov dx, 10
mov ah, 0ch ; put pixel
int 10h

colcount:
inc cx
int 10h

cmp cx, 20
JNE colcount

rowcount:
inc cx
int 10h

cmp cx, 20
JNE rowcount

推荐答案

mov ah, 0   ; set display mode function.
mov al, 13h ; mode 13h = 320x200 pixels, 256 colors.
int 10h     ; set it!

mov cx, 10  ;col
mov dx, 10  ;row
mov ah, 0ch ; put pixel

colcount:
inc cx
int 10h
cmp cx, 30
JNE colcount

mov cx, 10  ; reset to start of col
inc dx      ;next row
cmp dx, 30
JNE colcount

(根据您的代码) 这应该画一个正方形，

(Based on your code) this should draw a square,

每次绘制连续20个像素(通过增加cx-col)，然后转到下一行(增加dx-row) 并在该行中绘制20个像素.

each time drawing 20 pixels in a row(by increasing cx-col), then going to the next row(increase dx-row) and drawing 20 pixels in that row.

这将通过在20行中每行绘制20个像素来创建一个正方形

This will create a square by drawing 20pixels each row in 20 rows

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