正则表达式检查句号后的空格数-严格要求2 [英] Regex to check number of spaces after full stop - Strictly 2 required

问题描述

我需要检查在句号后放置一个空格的情况，然后将其替换为2个空格.我有正则表达式，但是Atom似乎调用无效.

I need to check occurrences where I have put one whitespace after a full-stop, and replace it by 2 spaces. I have the Regex for it, but Atom seems to call in invalid.

(?<=\.|\") {1,}(?=[a-zA-Z])

条件:

1. 句点后1个空格.
2. 如果句号以双引号引起来，则在引号后留1个空格.

上面的正则表达式非常适合我的情况，但是Atom无法对其进行验证.我需要将其用于现有文件.

The above regex works perfectly for my conditions however Atom is not able to validate it. I need to use it for existing files.

推荐答案

您可以使用

([."]) ([a-zA-Z])

，并替换为$1 $2.请参见 regex演示和

and replace with $1 $2. See the regex demo and a regex graph:

详细信息

• ([."])-组1(其值由替换模式中的$1反向引用引用):.或"
• -一个空格(使用\s匹配任何空白)
• ([a-zA-Z])-组2($2):ASCII字母.

• ([."]) - Group 1 (its value is referred to with $1 backreference from the replacement pattern): . or "
• - a space (use \s to match any whitespace)
• ([a-zA-Z]) - Group 2 ($2): an ASCII letter.

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