如何在Java中使用正则表达式非捕获组进行字符串替换 [英] How to use regex non capturing group for string replace in java

问题描述

我需要在新版本中更改AssemblyVersion.我使用Java代码string.replaceAll(regexPattern,updatedString);

I had a requirement to change AssemblyVersion on new build. I do it using java code string.replaceAll(regexPattern,updatedString);

此代码可以在正常的正则表达式模式下正常工作，但是我无法在此模式下使用非捕获组.我想使用非捕获组来确保除了捕获所需的模式以外，不捕获其他模式.这是我尝试的代码:

This code works fine with normal regex patterns, but I am not able to use non-capturing groups in this pattern. I want to use non-capturing groups to make sure I don't capture patterns other than required one. This is the code I tried:

String str="[assembly: AssemblyVersion(\"1.0.0.0\")]";
str=str.replaceAll("(?:\\[assembly: AssemblyVersion\\(\"\\d\\.\\d\\.)?.*(?:\"\\)\\])?", "4.0");
System.out.println(str);

在这里，我想匹配字符串[assembly: AssemblyVersion(int.int)]并仅替换次要版本.

Here, I want to match string [assembly: AssemblyVersion(int.int)] and replace only minor version.

预期结果为[assembly: AssemblyVersion("1.0.4.0")]，但我得到的结果为4.04.0.

Expected outcome is [assembly: AssemblyVersion("1.0.4.0")], but I'm getting result as 4.04.0.

有人可以帮我吗?

推荐答案

为什么不使用先行搜索/后向搜索?

Why not use look-ahead / look-behind instead?

它们不具有捕获性，可以在这里轻松工作:

They are non-capturing and would work easily here:

str = str
    .replaceAll(
        "(?<=\\[assembly: AssemblyVersion\\(\"\\d\\.\\d\\.).*(?=\"\\)\\])",      
        "4.0"
    );

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