如何在UNIX中每行的末尾删除一个字符 [英] How to remove a character at the end of each line in unix

问题描述

我想在文件中每一行的末尾删除逗号,.除了在awk中使用子字符串功能之外，我该如何做.请建议我.谢谢

I would like to remove comma , at the end of each line in my file. How can I do it other than using substring function in awk. please suggest me.Thanks

样本输入

        SUPPLIER_PROC_ID BIGINT NOT NULL,
        BTCH_NBR INTEGER NOT NULL,
        RX_BTCH_SUPPLIER_SEQ_NBR INTEGER NOT NULL,
        CORRN_ID INTEGER NOT NULL,
        RX_CNT BYTEINT NOT NULL,
        DATA_TYP_CD BYTEINT NOT NULL,
        DATA_PD_CD BYTEINT NOT NULL,
        CYC_DT DATE NOT NULL,
        BASE_DT DATE NOT NULL,
        DATA_LOAD_DT DATE NOT NULL,
        DATA_DT DATE NOT NULL,
        SUPPLIER_DATA_SRC_CD BYTEINT NOT NULL,
        RX_CHNL_CD BYTEINT NOT NULL,
        MP_IMS_ID INTEGER NOT NULL,
        MP_LOC_ID NUMERIC(3,0),
        MP_IMS_ID_ACTN_CD BYTEINT NOT NULL,
        NPI_ID BIGINT,

推荐答案

您可以使用sed:

sed 's/,$//' file > file.nocomma

并删除所有最后一个字符:

and to remove whatever last character:

sed 's/.$//' file > file.nolast

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