如何在 Bash 中重复一个字符? [英] How can I repeat a character in Bash?

问题描述

我怎么能用 echo 做到这一点?

How could I do this with echo?

perl -E 'say "=" x 100'

推荐答案

没有简单的方法.但例如:

No easy way. But for example:

seq -s= 100|tr -d '[:digit:]'
# Editor's note: This requires BSD seq, and breaks with GNU seq (see comments)

或者可能是符合标准的方式:

Or maybe a standard-conforming way:

printf %100s |tr " " "="

还有一个 tput rep，但至于我手头的终端(xterm 和 linux)，他们似乎不支持它:)

There's also a tput rep, but as for my terminals at hand (xterm and linux) they don't seem to support it:)

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