如何用printf重复一个字符？ [英] How to repeat a char using printf?

问题描述

我想要做类似的printf（？，计数，字符）来重复一个字符计数倍。

I'd like to do something like printf("?", count, char) to repeat a character count times.

什么是正确的格式字符串来完成呢？

What is the right format-string to accomplish this?

编辑：是的，很明显，我可以打电话给的printf（）在一个循环，但是这正是我想避免

Yes, it is obvious that I could call printf() in a loop, but that is just what I wanted to avoid.

推荐答案

简短的回答 - 是的，长的答案：不是你想要的。

Short answer - yes, long answer: not how you want it.

您可以使用的printf 的％*的形式，它接受一个可变宽度。而且，如果你使用0作为你的价值进行打印，合并的与右对齐文本是零填充左侧。

You can use the %* form of printf, which accepts a variable width. And, if you use '0' as your value to print, combined with the right-aligned text that's zero padded on the left..

printf("%0*d\n", 20, 0);

生产：

00000000000000000000

使用我的舌头牢牢地铭刻在了我的脸颊，我提供了code这个小恐怖表演片段。

With my tongue firmly planted in my cheek, I offer up this little horror-show snippet of code.

有些时候，你只是爱做的事情的糟糕记住你为什么如此努力的时间休息。

Some times you just gotta do things badly to remember why you try so hard the rest of the time.

#include <stdio.h>

int width = 20;
char buf[4096];

void subst(char *s, char from, char to) {
    while (*s == from)
    *s++ = to;
}

int main() {
    sprintf(buf, "%0*d", width, 0);
    subst(buf, '0', '-');
    printf("%s\n", buf);
    return 0;
}

这篇关于如何用printf重复一个字符？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！