对键排序并以bash求和 [英] Sort keys and Sum their values in bash

问题描述

我有一个字符串列表(stdin)，如下所示:

I have a list of strings (stdin) like next:

1 pineapples
28 apples
16 oranges
8 apples
2 apples
2 oranges
56 pineapples

是否存在一种本机方式(例如sort和uniq -c)，我可以通过这种方式合并和求和:

Is there a native way (like sort & uniq -c) with which I can merge and sum them like this:

38 apples
18 oranges
57 pineapples

像sort |uniq -c一样，但不仅限于出现次数?

like sort |uniq -c do, but not only for occurrences number?

推荐答案

尝试以下方法:

awk '{a[$2] += $1} END{for (i in a) print a[i], i}' < in.txt

输出

38 apples
57 pineapples
18 oranges

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