awk搜索字符串并设置退出代码(如果存在) [英] awk search for string and set exit code if it exists

问题描述

我想检查两个地址之间是否存在一行，如果存在则返回退出代码0，如果不存在则返回1.我想我有一个可行的例子，但是我想知道是否有更干净的方法可以做到.或RedHat上也常见的其他工具.

I want to check if a line exists between two addresses and return an exit code 0 if it exists and 1 if it does not. I think I've got one possible example working, but I'm wondering if there is a cleaner way to do it; or perhaps a different tool that's also common on RedHat.

我的命令:

awk 'BEGIN{found=1}NR==1,/^Match/{ if ( $0 == "PermitRootLogin yes" ) \
    { found=0 } }END { exit found }' /etc/ssh/sshd_config

推荐答案

awk '/^PermitRootLogin yes$/{f=1} /^Match/{exit} END{exit !f}' /etc/ssh/sshd_config

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