特定行的AWK打印命令 [英] AWK print command for specific rows

问题描述

我的文件中有数百万条记录，我需要做的是打印1396至1400列以显示特定的行数，并且如果可以在excel或记事本中获取它.

I have millions of records in my file, what i need to do is print columns 1396 to 1400 for specific number of rows, and if i can get this in excel or notepad.

尝试过此命令

awk {print $1396,$1397,$1398,$1399,$1400}' file_name

但这正在每一行运行.

推荐答案

您需要一个条件来指定将操作应用于哪些行:

You need a condition to specify which rows to apply the action to:

awk '<<condition goes here>> {print $1396,$1397,$1398,$1399,$1400}' file_name

例如，仅对第50到100行执行此操作:

For example, to do this only for rows 50 to 100:

awk 'NR >= 50 && NR <= 100 {print $1396,$1397,$1398,$1399,$1400}' file_name

(根据您要执行的操作，您还可以选择比这复杂得多的选择模式.)

(Depending on what you want to do, you can also have much more complicated selection patterns than this.)

这是一个更简单的测试示例:

Here's a simpler example for testing:

awk 'NR >= 3 && NR <= 5 {print $2, $3}'

如果我在包含以下内容的输入文件上运行

If I run this on an input file containing

1 2 3 4
2 3 4 5
3 a b 6
4 c d 7
5 e f 8
6 7 8 9

我得到了输出

a b
c d
e f

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