如何删除逆向grep匹配上方和下方的行? [英] How to remove lines above and below an inverse grep match?

问题描述

我正在处理一些比我想要的更为冗长的输出，因此我试图使用grep将其缩减.输出看起来像这样……

I'm working with some output that is more verbose than I'd like, so I was trying to use grep to whittle it down. The output looks something like this…

path/to/file1:
No Problems Found

path/to/file3:
Problem Found

我想过滤掉所有与文件有关的输出，而不会出现问题.我可以通过grep -v "No Problems Found"用管道输送输出来删除其中的一行.我以为我可以按照grep -B 1 -A 1 -v "No Problems Found"的方式使用-B和-A，但事实证明，与-v结合使用时，它们不会反转.

I'd like to filter out all the output concerning files without problems. I'm able to remove one line of it by piping the output through grep -v "No Problems Found". I thought I'd then be able to use -B and -A along the lines of grep -B 1 -A 1 -v "No Problems Found" but it turns out those don't invert when used in conjunction with -v.

导出文件后，我可以在Vim中快速修改输出，但我想直接在命令行上进行.有任何想法吗?对于Awk或Sed来说，这是更好的工作吗?

I can modify the output pretty quickly in Vim, after I've exported the file, but I'd like to do it directly on the command line, if I can. Any ideas? Is this a better job for Awk or Sed?

推荐答案

或使用sed(在osx上为ged):

or with sed (gsed on osx):

sed ':a;N;$!ba;s/[^\n]*\nNo Problems Found\n//g'

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