如何让 grep 打印每个匹配行下方和上方的行? [英] How can I make grep print the lines below and above each matching line?

问题描述

我必须解析一个非常大的文件，我想使用命令 grep(或任何其他工具).

I have to parse a very large file and I want to use the command grep (or any other tool).

我想在每个日志行中搜索词 FAILED，然后在每个匹配行的上方和下方打印该行，以及匹配的行.

I want to search each log line for the word FAILED, then print the line above and below each matching line, as well as the matching line.

id : 15
Satus : SUCCESS
Message : no problem

<小时>

id : 15
Satus : FAILED
Message : connection error

<小时>

我需要打印:

---

And I need to print:

id : 15
Satus : FAILED
Message : connection error

推荐答案

grep 的 -A 1 选项会给你一行；-B 1 会给你前一行；和 -C 1 将两者结合起来，在前后给你一行，-1 做同样的事情.

grep's -A 1 option will give you one line after; -B 1 will give you one line before; and -C 1 combines both to give you one line both before and after, -1 does the same.

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