如何用多行搜索和替换多行 [英] How to search and replace multiple lines with multiple lines

问题描述

我查看了有关搜索和替换的其他答案，但我只是不理解模式.

I looked at other answers regarding search and replace, but I just can't understand the patterns.

如何更改文件的这一部分(行号153 ... 156)

How can I change this part of a file (line numbers 153 ... 156)

        let view = string.utf8
        offset.pointee += string.substring(to: range.lowerBound).utf8.count
        length.pointee = Int32(view.distance(from:range.lowerBound.samePosition(in: view), to:range.upperBound.samePosition(in: view)))
        return token

并将其替换为下面的行?

and replace it with the lines below?

        let view:String.UTF8View = string.utf8

        if let from = range.lowerBound.samePosition(in: view),
           let to = range.upperBound.samePosition(in: view) {
            offset.pointee += Int32(string[string.startIndex..<range.lowerBound].utf8.count)
            length.pointee = Int32(view.distance(from: from, to: to))
            return token
        } else {
            return nil
        }

推荐答案

这可能对您有用(GNU sed& Bash):

This might work for you (GNU sed & Bash):

sed $'153r replacementFile\n;153,156d' file

或对于大多数sed:

sed -e '153r replacementFile' -e '153,156d' file

或者，如果您愿意:

sed '153,156c\        let view:String.UTF8View = string.utf8\
    if let from = range.lowerBound.samePosition(in: view),\
       let to = range.upperBound.samePosition(in: view) {\
        offset.pointee += Int32(string[string.startIndex..<range.lowerBound].utf8.count)\
        length.pointee = Int32(view.distance(from: from, to: to))\
        return token\
    } else {\
        return nil\
    }' file

前一个\保留前导空间，其后的每一行除外，最后一行需要附加\.当空行由单个\表示时，SO中的markdown格式不正确(因此，我删除了替换行的第二行)，但是大多数shell应该如此.

N.B. The first \ preserves leading space and each line following except the last needs to be appended with \. The markdown in SO does not format properly when an empty line is represented by a single \ (so I removed the second line of the replacement) but most shells should.

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