如何获得包含带有sed或awk的MAC地址的字段号? [英] How can I get the field number that contains a MAC address with sed or awk?

问题描述

我正在尝试获取包含某种模式(在本例中为MAC地址)的字段号.想象一下，我们有这样的事情:

I'm trying to get the field number that contains a certain pattern (in this case a MAC address). Imagine we have something like this:

AAA BBB CCC xx:xx:xx:xx:xx:xx EEE FFF GGG

其中xx:xx ...是MAC地址，因此x是字母数字.

Where xx:xx... is a MAC address, so x's are alphanumeric.

如果使用该行作为输入，我想获取MAC地址所在的字段的编号.在这种情况下，为"4".

If I use that line as the input, I want to obtain the number of the field where the MAC address is. In this case, "4".

我在想sed或awk，但不知道如何输出字段号.

I was thinking of sed or awk, but don´t know how to output the field number.

推荐答案

使用NF遍历字段

使用for循环，使用POSIX字符类的十六进制数字对照正则表达式检查每个字段.找到匹配项后，打印匹配的字段号.

Loop Over Fields With NF

Use a for-loop to check each field against a regular expression, using the POSIX character class for hexadecimal digits. When a match is found, print the matching field number.

echo 'AAA BBB CCC 00:00:00:00:00:00 EEE FFF GGG' |
    awk '{ for (i=1; i<=NF; i++)
               if ($i ~ /^([[:xdigit:]]{2}:){5}[[:xdigit:]]$/)
                   print i
                   next
         }'
4

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