对目录中的所有文件执行命令 [英] Execute command on all files in a directory

问题描述

请有人提供代码以执行以下操作: 假设有一个文件目录，所有文件都需要通过程序运行.程序将结果输出到标准输出.我需要一个脚本，该脚本将进入目录，对每个文件执行命令，并将输出合并为一个大输出文件.

Could somebody please provide the code to do the following: Assume there is a directory of files, all of which need to be run through a program. The program outputs the results to standard out. I need a script that will go into a directory, execute the command on each file, and concat the output into one big output file.

例如，要在1个文件上运行命令:

For instance, to run the command on 1 file:

$ cmd [option] [filename] > results.out

推荐答案

以下bash代码将$ file传递给命令，其中$ file表示/dir中的每个文件

The following bash code will pass $file to command where $file will represent every file in /dir

for file in /dir/*
do
  cmd [option] "$file" >> results.out
done

示例

el@defiant ~/foo $ touch foo.txt bar.txt baz.txt
el@defiant ~/foo $ for i in *.txt; do echo "hello $i"; done
hello bar.txt
hello baz.txt
hello foo.txt

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