使用Bash在特定行之前插入文本 [英] Insert text before a certain line using Bash

问题描述

如何在第一行找到的字符串中插入一组行(大约5条)?

How can I insert a set of lines (about 5) into a file at the first place a string is found?

例如:

BestAnimals.txt

BestAnimals.txt

dog
cat
dolphin
cat

$将长颈鹿插入猫的BestAnimals.txt中"> NewBestAnimals.txt

$ "Insert giraffe to BestAnimals.txt before cat" > NewBestAnimals.txt

NewBestAnimals.txt

NewBestAnimals.txt

dog
giraffe 
cat
dolphin
cat

推荐答案

如果使用gnu sed:

If using gnu sed:

$ cat animals
dog
cat
dolphin
cat

$ sed  "/cat/ { N; s/cat\n/giraffe\n&/ }" animals
dog
giraffe
cat
dolphin
cat

1. 用(/cat/)匹配一行
2. 继续下一行(N)
3. 用插入和匹配的字符串替换匹配的模式，其中&代表匹配的字符串.

1. match a line with (/cat/)
2. continue on next line (N)
3. substitute the matched pattern with the insertion and the matched string, where & represent the matched string.

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