删除前一个/bash之前的所有内容 [英] Delete everything before last / in bash

问题描述

文件中的文件路径很多，如下所示:

I have many file paths in a file that look like so:

/home/rtz11/files/testfiles/547/prob547455_01

我想使用一个bash脚本，该脚本仅将所有文件名打印到屏幕上.所以基本上在最后一个/之后.我不想假设它的长度总是一样的，因为可能不一样.有没有办法删除最后一个/之前的所有内容?也许sed命令?任何帮助将不胜感激！

I want to use a bash script that will print all the filenames only to the screen. so basically after the last /. I don't want to assume that it would always be the same length because it might not be. Would there be a way to delete everything before the last /? Maybe a sed command? Any help would be greatly appreciated!

推荐答案

awk '{print $NF}' FS=/ input-file

'print $ NF'指示awk打印每行的最后一个字段，并分配FS =/来使字段分度符正斜杠.在sed中，您可以执行以下操作:

The 'print $NF' directs awk to print the last field of each line, and assigning FS=/ makes forward slash the field delimeter. In sed, you could do:

sed 's@.*/@@' input-file

只是删除所有内容，包括最后一个/.

which simply deletes everything up to and including the last /.

这篇关于删除前一个/bash之前的所有内容的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！