使用bash从文本文件中提取变量的值 [英] extracting a variable's value from text file using bash

问题描述

我正在使用Linux和bash. 我有一个简单的文本文件，如下所示:

I am using Linux and bash. I have a simple text file like below:

VAR1=100
VAR2=5
VAR3=0
VAR4=99

我想通过bash提取VAR2的值，即5.

I want to extract by means of bash the value of VAR2, that is 5.

我该怎么办?

推荐答案

最简单的方法可能是使用source或只是.来读取和执行文件.这将适用于您的示例，因为变量值中没有空格.否则，您需要使用grep + cut或awk，如其他答案所述.

The simplest way might be to use source or simply . to read and execute the file. This would work with your example, because there are no spaces in the variable values. Otherwise you need to use grep + cut or awk, as stated in other answers.

. /path/to/your/file
echo $VAR2

如dawg所述，这将使脚本中的其他变量也可用，并且可能会覆盖现有变量.

[edit] As stated by dawg, this would make the other variables available in your script too, and possibly overwrite existing variables.

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