用sed替换一行中的多个字符串 [英] replace multiple strings in one line with sed

问题描述

我有一个软件包名称列表，想删除一些带有sed

I have a list of packagenames and want to delete some of those with sed

echo "package1 package2 package24 package44 package66 package12345" > benoetigte_pakete.list

如何删除另一个列表中的某些内容?

How can I delete some of those that are in another list?

dellist="package24|package66"

我尝试了

cat benoetigte_pakete.list | sed "s/(package24|package66)//"

但这是行不通的.

推荐答案

在sed正则表达式中，您必须转义(，|和).

In sed regexps you have to escape (, |, and ).

您还需要使用g修饰符，以便它替换行上的所有匹配项，而不仅仅是第一个匹配项.

You also need to use the g modifier so it replaces all matches on the line, not just the first match.

dellist="package24|package66"
# escape the pipes
dellist=${dellist//|/\\|}
sed "s/\b\($dellist\)\b//g" benoietigte_packete.list

我添加了\b，因此它只匹配整个单词.

I've added the \b so it only matches whole words.

根据您使用的sed版本，还可以使用-E或-r选项来使用扩展的正则表达式.

Depending on the version of sed you have, you can also use the -E or -r options to use extended regular expressions.

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