用'X'替换一行中两个字符串之间的所有字符 [英] Replace all characters between two strings in a line by 'X'

问题描述

我想用相同数量的 X 字符更改(通过 bash 脚本使用 SED 命令)两个给定字符串之间的所有字符.如果说，第一个字符串是 %26Name%3d 而最后一个字符串是 %26，那么这两个字符串之间的任何内容我都想用相同数量的 X 字符.我正在读取文件.该文件大约为 1MB.

I want to change (via bash script using SED command) all the characters in between two given strings with an equal number of X characters. If say, the first string is %26Name%3d and the last sting is %26, then anything in between these two strings I want to replace with an equal number of X characters. I am reading a file in place. The file is roughly 1MB.

所以

SOMETHING%26Name%3dTHISTEXTNEEDSTOBE%26ELSE

到

SOMETHING%26Name%3dXXXXXXXXXXXXXXXXX%26ELSE  

OR 如果起始字符串是 %26Last%3d 并且结束字符串是 %26

OR if start string is %26Last%3d and ending string is %26

something%26Last%3d%2%2%4%2%4%3%5%%2%2%2%26else  

到

something%26Last%3dXXXXXXXXXXXXXXXXXXXXX%26else  

我在我的 bash 脚本中使用 sed 命令在下面尝试过，但效果不佳.

I tried below using the sed command in my bash script but didn't worked perfectly.

file=mylog.log
myAnd=\\%26
myEqual=\\%3d
startList=Name\|Last
end_str="\%26"
search_str="$myAnd""(""$startList"")""$myEqual"

sed -i -E ':a; s/('"$search_str"'X*)[^X](.*'"$end_str"')/\1X\2/; ta' "$file"

PS startList=Name\|Last 以上声明以及 myAnd 和 myEqual.

PS startList=Name\|Last above declaration and also of myAnd and myEqual.

示例:

SOME%26Name%3dTHISTEXTNEEDSTOBE%26Last%3dDUTTA  
to  
SOME%26Name%3dXXXXXXXXXXXXXXXXX%26Last%3dXXXXX  

推荐答案

这是一个 sed 解决方案:

Here is a sed solution:

sed -e :a -e 's/\(%26Name%3d[X]*\)[^X]\(.*%26\)/\1X\2/;ta'

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