批量复制所有文件而不会覆盖 [英] Batch copying all files without overwriting

问题描述

set dSource=C:\Games\Steam\steamapps
set dTarget=E:\Demos
set fType=*.dem

xcopy/i "%dSource%\%fType%" "%dTarget%"

这是我当前必须复制的所有文件，但是如何获取它来复制所有文件并重命名具有相同名称的文件，以便将两个副本都保存在目标文件夹中.

This is what I currently have to copy all my files, but how can I get it to copy all the files and rename any that have the same name, so that both copies are kept in the destination folder.

例如:
source:demo.dem
目的地:demo.dem

Eg:
source:demo.dem
destination:demo.dem

转到:
destination:demo.dem，demo(1).dem

Goes to:
destination:demo.dem, demo(1).dem

推荐答案

尝试使用copy的此解决方案:

Try this solution with copy:

@echo off &setlocal
set "dSource=C:\Games\Steam\steamapps"
set "dTarget=E:\Demos"
set "fType=*.dem"

for %%i in ("%dSource%\%fType%") do if not exist "%dtarget%\%%~nxi" (copy /b "%%~i" "%dtarget%") else call :process "%%~i"
goto :eof

:process
set /a cnt=-1
:loop
set /a cnt+=1
set "fname=%dtarget%\%~n1(%cnt%)%~x1"
if exist "%fname%" goto :loop
copy /b "%~1" "%fname%"
goto :eof

endlocal

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