用新文件替换旧文件 [英] Replace old file with new file

问题描述

我正在尝试编写一个脚本，用以下格式出现的新文件内容替换旧文件内容:

I am trying to write a script to replace old files content with new files content which is appearing in the following format:

旧文件:something.txt
新文件:something.txt.new

Old file : something.txt
New file : something.txt.new

旧文件需要替换为新文件内容
要重命名的新文件名，而无需新建
旧文件需要删除

Old file need to replaced with New file contents
New File name to be rename without new
Old file need to be deleted

以下脚本不起作用:请重写:

Below script is not working :Could you please rewrite:

@echo off
setlocal enabledelayedexpansion
set FOLDER_PATH=D:\test
for %%f in (%FOLDER_PATH%*) do if %%f neq %~nx0 (
    set basename=test
    ren *.txt.new !basename!.txt
)
PAUSE

我的文件夹中有很多文件，需要遍历每个文件，只需要在每次迭代中用旧文件名填充basename变量即可.

i have many files in folder and need to iterate through each file,only i need is basename variable need to be filled with the name of the old file name in each iteration

推荐答案

无效的问题无效的答案

源1

@echo off
set FOLDER_PATH=D:\test
cd /d "%FOLDER_PATH%"
ren "*.txt.new" "*.txt"

源2

@echo off
set FOLDER_PATH=D:\test
cd /d "%FOLDER_PATH%"
ren "*.txt" "*.txt.new"

这篇关于用新文件替换旧文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！