为什么我会收到“回声打开"的消息尝试批量打印变量时 [英] Why I am getting "Echo is on" when trying to print a variable in batch

问题描述

我试图执行一个简单的批处理文件脚本:

I tring to excute a simple batch file scripts :

echo %1
set var = %1
echo %var%

当我在XP中运行它时，它会给我预期的输出，但是当我在Vista或Windows 7中运行它时，在尝试打印(回显)值时却显示回显已打开".

When I am running it in XP, it is giving me expected output, but When I am running it in Vista or windows 7, I am getting "Echo is On" when trying to print (echo) value.

下面是程序的输出:

G:\2012>abc.bat 1

G:\2012>echo 1
1

G:\2012>set var = 1

G:\2012>echo
ECHO is on.

G:\2012>

推荐答案

摆脱设置表达式中的空格.等号(=)的两侧可以并且应该没有空格

Get rid of the spaces in your set expression. There can and should be no spaces on either side of the equal sign (=)

set var=%1

顺便说一句:我通常在关闭@echo的情况下开始所有批处理文件，并在打开@echo的情况下结束它们，因此可以避免将代码与批处理文件的输出混淆.它只是使您的批处理文件输出更好，更干净.

BTW: I usually start all my batch files with @echo off, and end them with @echo on too, so I can avoid mixing code with the output of the batch file. It just makes your batch file output a little nicer and cleaner.

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