批处理文件将最新的7个文件保留在一个子文件夹中 [英] Batch file that keeps the 7 latest files in a subfolder

问题描述

有人可以帮助我创建批处理文件吗?基本上，我的目标是创建一个批处理文件，该文件将在指定目录的所有文件夹中保留最新的7个文件(换句话说，最新的).

Can anyone help me create a batch file? Basically, my goal is to create a batch file that will keep the latest 7 files (in other words, the newest) in the all folders from specify directory.

我知道了

set file2del=
for /f "skip=7" %%A in ('dir /b/o-d') do set file2del=%%A
if not "%file2del%"=="" del "%file2del%"

但这适用于当前目录.

推荐答案

尝试一下:

首先将FOR /D与/R开关一起使用，以递归方式循环播放所有文件夹(开始蝙蝠的位置).并在每个目录上应用FOR /F循环.

First use FOR /D with the /R Switch to recursively loop on all folder (from where the bat is started). and apply the FOR /F loop on each directory.

@echo off

for /d /r %%a in (*) do (echo Treating Diretory ==^>  %%a
  for /f "skip=7" %%b in ('dir /b/o-d "%%a"') do del "%%a\%%b"
)

如果您需要更详细的信息，可以使用计数器代替SKIP=7:

If you need something more detailled you can use a counter in place of the SKIP=7 :

@echo off
setlocal enabledelayedexpansion


for /d /r %%a in (*) do (echo Treating Diretory ==^>  %%a
  set /a $count=1
  for /f %%b in ('dir /b/o-d "%%a"') do (
          if !$count! LEQ 7 (
              echo Keeping File[!$count!] ==^> %%b
              set /a $count+=1
          ) else (echo Deleting File ==^> %%a\%%b
                  del "%%a\%%b")
   )
)

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