批处理脚本:搜索文件，提取编号，然后复制到新文件中 [英] Batch Scripting:search file, extract numbers, and copy into new file

问题描述

我是批处理脚本的新手，并且有一个问题.我想知道是否有可能按要求搜索.txt文件并获取指定的数据并复制到新的.txt文件中?

I'm new to batch scripting and have a question. I was wondering if it's possible to search a .txt file by requirements and take data specified and copy into a new .txt file?

就像我有50行9位数字和一堆我不需要的废话，我可以说， 对于以1,2,3,4,5,6,7,8或9开头的任何行...请使用前9位数字并将其复制到新文件中，以用于文件中的所有行??? "

Like if I have 50 lines with 9 digit numbers and a bunch of other crap I don't need after them can I say, "For any line beginning with a 1,2,3,4,5,6,7,8,or 9...take the first 9 digits and copy them into a new file, for all lines in the file???"

我认为这比尝试删除所有其他内容要容易.让我知道您是否知道如何执行此操作！谢谢.

I thought this would be easier than trying to delete all the other stuff. Let me know if you know anything about how to do this! Thanks.

以下是一行内容的示例:
123456789 @ example
我只需要从大约50行中提取9位数字即可.

Here's an example of what one line looks like:
123456789@example
and I just need to extract the 9 digit numbers from about 50 lines of this.

推荐答案

您可以使用FINDSTR过滤掉所有不以9位数字开头的行.然后，FOR/F可以逐行读取结果.设置了一个变量，子字符串操作仅保留前9位数字.

You can use FINDSTR to filter out all lines that do not start with 9 digits. Then FOR /F can read the result, line by line. A variable is set, and a substring operation preserves just the first 9 digits.

@echo off
setlocal enableDelayedExpansion
(
  for /f %%A in (
    'findstr "^[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]" yourFile.txt'
  ) do (
    set "ln=%%A"
    echo !ln:~0,9!
  )
)>newFile.txt

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