同时批量处理多个文件 [英] Batch processing multiple files at the same time

问题描述

我有这个批处理命令

@echo off
FOR %%i in (C:\input\*.*) DO (
echo processing %%i
if not exist "C:\output\%%i" process.exe "%%i" -out "C:\output\%%i"
)
echo ---- finished ----
pause

在这里，我的工具process.exe循环处理目录中的所有文件-如果结果尚不存在.

Here my tool process.exe processes in a loop all files within a directory - if a result doesn't already exist.

现在我的CPU足够快，可以同时在2个或3个文件上运行此process.exe，这将大大加快文件的处理速度.

Now my CPU is fast enough to run this process.exe on 2 or 3 files at the same time which would make the processing of the files much faster.

问题:如何更改命令以使批处理文件同时处理2-3个文件?

Question: How do I have to change the command to make my batch file processing 2-3 files at the same time?

推荐答案

以下内容将启动进程，最大计数为%bunch%.每当其中一个完成时，就会启动另一个.

The following starts processes up to a max count of %bunch%. Whenever one of them finishes, another one will be started.

@ECHO off
setlocal enabledelayedexpansion
set bunch=3

for %%a in (C:\input\*) do (
  call :loop 
  echo processing: %%a
  start "MyCommand" cmd /c timeout 60
  REM if not exist "C:\output\%%i" start "MyCommand" cmd /c process.exe "%%i" -out "C:\output\%%i"

)
call :loop
goto :eof

:loop  REM waits for available slot
echo on
for /f %%x in ('tasklist /fi "windowtitle eq MyCommand"  ^| find /c "cmd.exe"') do set x=%%x
if %x% geq %bunch% goto :loop
echo off
goto :eof

我没有您的process.exe，所以我不得不猜测.但是REM ed行应该适合您. (timeout命令只是为了显示原理)

I don't have your process.exe, so I have to guess. but the REMed line should work for you. (the timeout command is just to show the princip)

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