在关键字之后和问号之前匹配的正则表达式 [英] Regex that wil match after keyword and before question mark

问题描述

我正用以下测试字符串卡在regex101上:

I'm getting stuck on regex101 with the following test string:

https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp = 24

我正在尝试匹配介于两者之间的所有内容:recepten-zoeken/和?

I'm trying to match everything in between: recepten-zoeken/ and ?

由于我是新手，正在编写正则表达式，因此我目前的尝试无济于事.任何人想要加入吗?

My current tries lead me nowhere as i'm very novice writing regexes. Anyone wanting to chip in?

这是我目前拥有的:

.(?=([[^/recepten-zoeken/]?)* $)

.(?=([^/recepten-zoeken/]?)*$)

推荐答案

使用捕获组.(()中的括号表示捕获组)

Use capturing group.(() brackets indicates capturing group)

捕获到最后一个问号

尝试此正则表达式\/recepten-zoeken\/(.*)\?

说明:-

• \/匹配正斜杠
• recepten-zoeken字面上匹配
• \/匹配正斜杠
• (.*)捕获组中的所有值(换行符除外)，直到字符串中的最后一个问号(这将包含您的值)
• \?字面上匹配

• \/ Match forward slash
• recepten-zoeken Match literally
• \/ Match forward slash
• (.*) Capture in a group all value(except new line) upto last question mark in string(This will contain your value)
• \? Match literally

//-------------------------select upto last ? -----------------------------

str = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp=24";
var myRegexp = /\/recepten-zoeken\/(.*)\?/;
console.log(myRegexp.exec(str)[1]);

捕获第一个问号

尝试此正则表达式\/recepten-zoeken\/([^?]*)\?.

说明:-

• \/匹配正斜杠
• recepten-zoeken字面上匹配
• \/匹配正斜杠
• ([^?]*)将所有值(?除外)捕获到字符串中的第一个问号(其中将包含您的值)(此处[^?]表示匹配除?以外的任何字符)
• \?字面上匹配

• \/ Match forward slash
• recepten-zoeken Match literally
• \/ Match forward slash
• ([^?]*) Capture in a group all value(except ?) upto first question mark in string(This will contain your value)(here [^?] means match any character except ?)
• \? Match literally

//-------------------------select upto first ? -----------------------------

var str = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen?:winter?Nrpp=24";
var myRegexp = /\/recepten-zoeken\/([^?]*)\?/;
console.log(myRegexp.exec(str)[1]);

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