如何仅获取二进制文件的前十个字节 [英] How to get only the first ten bytes of a binary file

问题描述

我正在编写一个bash脚本，该脚本需要获取文件的标头(前10个字节)，然后在另一节中获取除前10个字节以外的所有内容.这些是二进制文件，在前10个字节中可能都有\0和\n.似乎大多数实用程序都可使用ASCII文件.什么是完成此任务的好方法?

I am writing a bash script that needs to get the header (first 10 bytes) of a file and then in another section get everything except the first 10 bytes. These are binary files and will likely have \0's and \n's throughout the first 10 bytes. It seems like most utilities work with ASCII files. What is a good way to achieve this task?

推荐答案

要获取前10个字节(如前所述):

To get the first 10 bytes, as noted already:

head -c 10

要获取除前10个字节以外的所有字节(至少使用GNU tail):

To get all but the first 10 bytes (at least with GNU tail):

tail -c+11

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