如何将32位二进制转换为浮点数 [英] How to convert 32-bit binary to float

问题描述

我想执行从32位二进制到python浮点数的IEEE 754转换.

I want to perform IEEE 754 conversion from 32-bit binary to float in python.

我已经尝试过了

import struct

f = int('11000001101011000111101011100001', 2)
print struct.unpack('f', struct.pack('i', f))[0]

但这不适用于带负号位的数字.

but this doesn't work for numbers with negative sign bit.

预期的输出应如下所示:

Expected output should be like this:

bintofloat(11000001101011000111101011100001)
>>> -21.56

推荐答案

您可以按以下方式使用struct:

You could use struct as follows:

import struct

f = int('01000001101011000111101011100001', 2)
print struct.unpack('f', struct.pack('I', f))[0]

f = int('11000001101011000111101011100001', 2)
print struct.unpack('f', struct.pack('I', f))[0]

为您提供以下输出:

21.5599994659
-21.5599994659

这完全取决于整数的表示方式.

It all depends on how the integer is represented though.

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