数字的二进制补码和其负数差? [英] Two's Complement of a number and its negative number difference?

问题描述

因此，我被告知二进制补码通常用于查找数字的补码，而我仅将其用于补正数(即positve->负转换)，但是我在书中仅举了一个例子，问我以下:

So i was told that two's complement is usually to used to find complement of a number and I used it only to complement positive numbers (i.e positve --> negative conversion) however I just got an example in book which asks me the following :

以8位二进制2的补码表示23，-23和-9 表格

Express 23, -23, and -9 in 8-bit binary two’s Complement form

现在那是什么意思? 23表示二进制中的-23，-23表示23中的23?

now what does that mean? 23 means -23 in binary and -23 means 23 ?

sorta在那里困惑

sorta confused over there

推荐答案

2的补数用于表示负数，而负数又可以用于进行减法.

2's complement is used to represent negative numbers, which in turn, can be used to do subtraction.

23 = 00010111b

要获得-23(2的23的补数)，请翻转所有位，然后添加1:

To get -23 (2's complement of 23), flip all the bits, and add 1:

 11101000b + 1
=11101001b (-23)

-9是9的2的补码.9是

-9 is the 2's complement of 9. 9 is

00001001b

所以-9是

11110111b (Flipping and add +1)

另请参见此处

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