什么是0xFF?为什么将它移位24次? [英] What is 0xFF and why is it shifted 24 times?

问题描述

#define SwapByte4(ldata) \
   (((ldata & 0x000000FF) << 24) | \
   ((ldata & 0x0000FF00) << 8) | \
   ((ldata & 0x00FF0000) >> 8) | \
   ((ldata & 0xFF000000) >> 24))

0x000000FF代表什么?我知道十进制15以F表示为十六进制，但是为什么<< 24?

What does that 0x000000FF represent? I know that decimal 15 is represented in hex as F, but why is it << 24?

推荐答案

这是一个十六进制值0x12345678，以二进制形式编写，并带有一些位位置的注释:

Here is a hex value, 0x12345678, written as binary, and annotated with some bit positions:

|31           24|23           16|15            8|7         bit 0|
+---------------+---------------+---------------+---------------+
|0 0 0 1 0 0 1 0|0 0 1 1 0 1 0 0|0 1 0 1 0 1 1 0|0 1 1 1 1 0 0 0|
+---------------+---------------+---------------+---------------+

...这是0x000000FF:

...and here is 0x000000FF:

+---------------+---------------+---------------+---------------+
|0 0 0 0 0 0 0 0|0 0 0 0 0 0 0 0|0 0 0 0 0 0 0 0|1 1 1 1 1 1 1 1|
+---------------+---------------+---------------+---------------+

因此按位与运算仅选择原始值的后8位:

So a bitwise AND selects just the bottom 8 bits of the original value:

+---------------+---------------+---------------+---------------+
|0 0 0 0 0 0 0 0|0 0 0 0 0 0 0 0|0 0 0 0 0 0 0 0|0 1 1 1 1 0 0 0|
+---------------+---------------+---------------+---------------+

...并将其左移24位，即可将其从最低8位移至最高位:

...and shifting it left by 24 bits moves it from the bottom 8 bits to the top:

+---------------+---------------+---------------+---------------+
|0 1 1 1 1 0 0 0|0 0 0 0 0 0 0 0|0 0 0 0 0 0 0 0|0 0 0 0 0 0 0 0|
+---------------+---------------+---------------+---------------+

...十六进制为0x78000000.

...which is 0x78000000 in hex.

其他部分对输入的其余8位部分起作用:

The other parts work on the remaining 8-bit portions of the input:

  0x12345678
& 0x000000FF
  ----------
  0x00000078 << 24 = 0x78000000       (as shown above)

  0x12345678
& 0x0000FF00
  ----------
  0x00005600 <<  8 = 0x00560000

  0x12345678
& 0x00FF0000
  ----------
  0x00340000 >>  8 = 0x00003400

  0x12345678
& 0x00000000
  ----------
  0x12000000 >> 24 = 0x00000012

                   | ----------
                     0x78563412

因此，总体效果是将32位值ldata视为四个8位字节的序列，并颠倒它们的顺序.

so the overall effect is to consider the 32-bit value ldata as a sequence of four 8-bit bytes, and reverse their order.

这篇关于什么是0xFF?为什么将它移位24次?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！