IEEE 754用C语言转换为十进制 [英] IEEE 754 to decimal in C language

问题描述

我正在寻找将浮点数转换为C中十进制表示形式的最佳方法.我将尝试举一个例子:用户在IEEE754(1 1111111 10101 ...)中引入了一个数字必须返回十进制表示形式(例如25.6)
我已经尝试过使用掩码和按位运算，但是没有任何逻辑结果.

I'm looking the best way to transform a float number to its decimal representation in C. I'll try to give you an example: the user introduces a number in IEEE754 (1 1111111 10101...) and the program has to return the decimal representation (ex. 25.6)
I've tried with masks, and bitwise operations, but I haven't got any logical result.

推荐答案

我相信以下内容正在执行您描述的操作:

I believe the following is performing the operation you describe:

我使用int作为中间表示，因为它的位数与浮点数(在我的机器上)相同，并且可以轻松地从二进制字符串进行转换.

I use the int as an intermediate representation because it has the same number of bits as the float (on my machine), and it allowed easy conversion from the binary string.

#include <stdio.h>

union {
    int i;
    float f;
} myunion;

int binstr2int(char *s)
{
    int rc;
    for (rc = 0; '\0' != *s; s++) {
        if ('1' == *s) {
            rc = (rc * 2) + 1;
        } else if ('0' == *s) {
            rc *= 2;
        } 
    }
    return rc;
}

int main(void) {

    // the input binary string (4 bytes)
    char * input = "11000000110110011001100110011010";
    float *output;


    // convert to int, sizeof(int) == sizeof(float) == 4
    int converted = binstr2int(input); 

    // strat 1: point memory of float at the int
    output = (float*)&converted; // cast to suppress warning
    printf("%f\n", *output); // -6.8

    // strat 2: use a union to share memory 
    myunion.i = converted; 
    printf("%f\n", myunion.f); // -6.8

    return 0;
}

正如@DanielKamilKozar所指出的，该int的正确类型是uint32_t.但是，这需要包含<stdint.h>.

As @DanielKamilKozar points out, the correct type for that int is uint32_t. However, that would require including <stdint.h>.

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