在节点中将ieee754转换为十进制 [英] Convert ieee754 to decimal in node

查看:460
本文介绍了在节点中将ieee754转换为十进制的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在节点< Buffer 42 d9 00 00> 中有一个缓冲区,该缓冲区应该代表十进制108.5。我正在使用此模块尝试对缓冲区进行解码: https://github.com/feross/ieee754

I have a buffer in node <Buffer 42 d9 00 00> that is supposed to represent the decimal 108.5. I am using this module to try and decode the buffer: https://github.com/feross/ieee754.

ieee754.read = function (buffer, offset, isLE, mLen, nBytes)

参数含义如下:

buffer = the buffer
offset = offset into the buffer
value = value to set (only for write)
isLe = is little endian?
mLen = mantissa length
nBytes = number of bytes

我尝试阅读值: ieee754.read(buffer,0,false,5832704,4)但没有得到预期的结果。尽管我不确定 mLen 参数,但我认为我正确调用了该函数。

I try to read the value: ieee754.read(buffer, 0, false, 5832704, 4) but am not getting the expected result. I think I am calling the function correctly, although I am unsure about the mLen argument.

推荐答案

[我发现]节点Buffer类具有内置的功能: buffer.readFloatBE(0)

[I discovered that] the node Buffer class has that ability built in: buffer.readFloatBE(0).

这篇关于在节点中将ieee754转换为十进制的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆