io_service :: run()的专用线程 [英] dedicated thread for io_service::run()

问题描述

我想提供一个由一个全局线程驱动的全局io_service.很简单，我只有线程主体调用io_service::run().但是，如果没有工作要做，则这不起作用，因为run(run_one，poll，poll_one)返回.但是，如果线程重复调用run()，则在无事可做时将忙于循环.

I want to provide a global io_service that is driven by one global thread. Simple enough, I just have the thread body call io_service::run(). However, that doesn't work as run (run_one, poll, poll_one) return if there is no work to do. But, if the thread repeatedly calls run(), it will busy loop when there is nothing to do.

我正在寻找一种方法来使线程阻塞，而io_service中没有任何工作要做.我可以将全局事件添加到混合中，以阻止线程继续运行.但是，这将要求io_service的用户在每次使用该服务时通知事件.不是理想的解决方案.

I'm looking for a way to get the thread to block while there isn't any work to be done in the io_service. I could add a global event to the mix for the thread to block on. However, that would require users of the io_service to notify the event every time they used the service. Not the ideal solution.

注意:没有实际的全局变量，并且我从不使用事件进行并发，我只是根据我的实际需要将问题简化了.真正的目标是asio::deadline_timer子类，它不需要io_service作为构造参数.

Note: there are no actual globals and I never use events for concurrency I just simplified the problem down to my exact need. The real goal is a asio::deadline_timer subclass that doesn't require an io_service as a construction parameter.

推荐答案

您需要创建一个io_service::work对象.

请参阅文档的此部分:

阻止io_service耗尽工作

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