使用Boost.python将Python列表传递给C ++向量 [英] Passing Python list to C++ vector using Boost.python

问题描述

如何将对象类型ClassName的Python列表传递给接受vector<ClassName>的C ++函数?

How do I pass a Python list of my object type ClassName to a C++ function that accepts a vector<ClassName>?

我发现的最好的是这样的:示例.不幸的是，代码崩溃了，我似乎无法弄清楚为什么.这是我用的:

The best I found is something like this: example. Unfortunately, the code crashes and I can't seem to figure out why. Here's what I used:

template<typename T>
void python_to_vector(boost::python::object o, vector<T>* v) {
    try {
      object iter_obj = object(handle<>(PyObject_GetIter(o.ptr())));
      return;
      for (;;) {
          object obj = extract<object>(iter_obj.attr("next")());
          // Should launch an exception if it cannot extract T
          v->emplace_back(extract<T>(obj));
      }
    } catch(error_already_set) {
        PyErr_Clear();
        // If there is an exception (no iterator, extract failed or end of the
        // list reached), clear it and exit the function
        return;
    }
}

推荐答案

假定您具有采用std::vector<Foo>

void bar (std::vector<Foo> arg)

处理此问题的最简单方法是将vector暴露给python.

The easiest way to handle this is to expose the vector to python.

BOOST_PYTHON_MODULE(awesome_module)
{
    class_<Foo>("Foo")
        //methods and attrs here
    ;

    class_<std::vector<Foo> >("VectorOfFoo")
        .def(vector_indexing_suite<std::vector<foo> >() )
    ;

    .def("bar", &bar)
}

所以现在在python中，我们可以将Foo s插入vector并将向量传递到bar

So now in python we can stick Foos into a vector and pass the vector to bar

from awesome_module import *
foo_vector = VectorOfFoo()
foo_vector.extend(Foo(arg) for arg in arglist)
bar(foo_vector)

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