揭露Boost.Python的指针 [英] Exposing a pointer in Boost.Python

问题描述

我有这个非常简单的C ++类：

I have this very simple C++ class:

class Tree {
    public:
        Node *head;
};
BOOST_PYTHON_MODULE(myModule)
{

   class_<Tree>("Tree")
        .def_readwrite("head",&Tree::head)
    ;

}

我要访问在Python头变量，但我看到的信息是：

I want to access the head variable from Python, but the message I see is:

No to_python (by-value) converter found for C++ type: Node*

据我了解，这是因为Python的是吓坏了，因为它没有指针的概念。如何从Python中访问头变量？

From what I understand, this happens because Python is freaking out because it has no concept of pointers. How can I access the head variable from Python?

我明白我应该使用的封装，但我目前用卡需要一个非封装解决方案。

I understand I should use encapsulation, but I'm currently stuck with needing a non-encapsulation solution.

推荐答案

当然，我找到了答案10分钟问这个问题后......这里是它是如何做的：

Of course, I find the answer ten minutes after asking the question...here's how it's done:

class_<Tree>("Tree")
    .add_property("head",
     make_getter(&Tree::head, return_value_policy<reference_existing_object>()),
     make_setter(&Tree::head, return_value_policy<reference_existing_object>()))
;

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