Python瓶-如何在不使用DOS的情况下上传媒体文件 [英] Python bottle - How to upload media files without DOSing the server
问题描述
我正在使用这个问题的答案,并看到了以下评论:>
I was using the answer from this question and saw the comment:
raw = data.file.read() # This is dangerous for big files
如何在不执行此操作的情况下上传文件?到目前为止,我的代码是:
How do I upload the file without doing this? My code so far is:
@bottle.route('/uploadLO', method='POST')
def upload_lo():
upload_dir = get_upload_dir_path()
files = bottle.request.files
print files, type(files)
if(files is not None):
file = files.file
print file.filename, type(file)
target_path = get_next_file_name(os.path.join(upload_dir, file.filename))
print target_path
shutil.copy2(file.read(), target_path) #does not work. Tried it as a replacement for php's move_uploaded_file
return None
给出以下输出:
127.0.0.1 - - [03/Apr/2014 09:29:37] "POST /uploadLO HTTP/1.1" 500 1418
Traceback (most recent call last):
File "C:\Python27\lib\site-packages\bottle.py", line 862, in _handle
return route.call(**args)
File "C:\Python27\lib\site-packages\bottle.py", line 1727, in wrapper
rv = callback(*a, **ka)
File "C:\dev\project\src\mappings.py", line 83, in upload_lo
shutil.copy2(file.read(), target_path)
AttributeError: 'FileUpload' object has no attribute 'read'
我正在使用python bottle v.12,dropzone.min.js和mongodb.我也在使用本教程:
I am using python bottle v.12, dropzone.min.js, and mongodb. I also am using this tutorial:
http://www.startutorial.com/articles/view/how-to-build-a-file-upload-form-using-dropzonejs-and-php
推荐答案
这称为文件提取":
raw = data.file.read()
和您不会想要这么做(至少在这种情况下如此).
and you don't want to do it (at least in this case).
这是一种读取大小未知(可能很大)的二进制文件的更好方法:
Here's a better way to read a binary file of unknown (possibly large) size:
data_blocks = []
buf = data.file.read(8192)
while buf:
data_blocks.append(buf)
buf = data.file.read(8192)
data = ''.join(data_blocks)
如果累计大小超过某个阈值,您可能还想停止迭代.
You may also want to stop iterating if the accumulated size exceeds some threshold.
希望有帮助!
PART 2
您问过有关限制文件大小的问题,因此,这是一个修改后的版本,用于执行此操作:
You asked about limiting the file size, so here's an amended version that does that:
MAX_SIZE = 10 * 1024 * 1024 # 10MB
BUF_SIZE = 8192
# code assumes that MAX_SIZE >= BUF_SIZE
data_blocks = []
byte_count = 0
buf = f.read(BUF_SIZE)
while buf:
byte_count += len(buf)
if byte_count > MAX_SIZE:
# if you want to just truncate at (approximately) MAX_SIZE bytes:
break
# or, if you want to abort the call
raise bottle.HTTPError(413, 'Request entity too large (max: {} bytes)'.format(MAX_SIZE))
data_blocks.append(buf)
buf = f.read(BUF_SIZE)
data = ''.join(data_blocks)
这不是完美的,但是它很简单,而且IMO足够好.
It's not perfect, but it's simple and IMO good enough.
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