scanf读取后输入缓冲区是否被清除？ [英] Does the input buffer gets cleared after scanf reads?

问题描述

读取 scanf 后是否清除输入缓冲区？

Does the input buffer gets cleared after scanf reads?

#include <stdio.h>

int main(void) 
{
    int a, b;
    scanf("%d", &a);//I inputted 3
    scanf("%d", &b);//I inputted 4
}

所以当我输入 4 时， 3 是否存在于输入缓冲区中？

So when I gave the input 4 was 3 present in the input buffer?

推荐答案

当我给输入4时，输入缓冲区中是否有3个？

So when I gave the input 4 was 3 present in the input buffer?

否，这3被消耗了。

您不能重新读取它（以int或其他方式读取）。

You cannot re-read it (as int or otherwise).

如果输入 3< enter> ; 被消耗，并且缓冲区仅包含< enter> 。然后，您输入 4< enter> 添加到缓冲区中。第2个scanf（*）消耗了初始输入，而第4个剩余的< enter> 用于下一个输入操作。

If you input "3<enter>" the 3 is consumed and the buffer contains just the "<enter>". You then type "4<enter>" which is added to the buffer. The 2nd scanf (*) consumes the initial enter and the 4 leaving "<enter>" for the next input operation.

（*）转换说明符％d 跳过可选的前导空格，并（尝试）将其余输入转换为整数（如果没有发生错误）

(*) the conversion specifier "%d" skips optional leading whitespace and (tries to) converts the rest of the input to integer (if no errors occur).

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