如何清除Java中的输入缓冲区 [英] how to clear input buffer in java

问题描述

为避免在控制台中输入任何不必要的字符，例如 \n

For avoiding any unwanted character which has been entered in console like \n

，我们使用 nextInt（）或 nextLine（）等。

但是在这些情况下，控件实际上向前走了一步，留下了不需要的字符串或类似内容。
但是我想删除或清除 buffer 的内存，系统会在其中删除其他不需要的数据。
例如->

But in these cases actually the control is going a step ahead leaving the unwanted string or something like this. But I want to delete or flush out the memory of buffer in which other unwanted data is taken by the system. For example -->

Scanner scan=new Scanner(System.in);
scan.nextInt();
scan.nextline();//this statement will be skipped

系统将 \n 作为一行输入给定的整数旁边。
在这种情况下，不使用 scan.nextLine（），我只想清除/清空存储 \n 的缓冲存储器。
现在，请告诉我如何删除Java中的输入缓冲存储器

because the system is taking \n as a line next to the integer given as input. In this case without using scan.nextLine() I want to simply clear/flush out the buffer memory where the \n was stored. Now please tell me how to delete the input buffer memory in java

谢谢。 ：）

推荐答案

您可以使用它清除缓冲区中的所有现有数据：

You can use this to clear all existing data in the buffer:

while(sc.hasNext()) {
    sc.next();
}

如果仅这样做是为了删除换行符（\n）从输入中，您可以使用：

If you are only doing this to remove the newline (\n) characters from the input, you can use:

while(sc.hasNext("\n")) {
    sc.next();
}

如果目标是仅读取整数并跳过任何其他字符，则将工作：

If the goal is to only read integers and skip any other characters, this would work:

while(sc.hasNext() && !sc.hasNextInt()) {
    sc.next();
}

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