通过一定条件查找数组中元素的最后一个索引 [英] Find last index of element inside array by certain condition

问题描述

假设我有一个对象数组：

Let's say I have an array of objects:

[{'a': 'something', 'b':12},
{'a': 'something', 'b':12},
{'a': 'somethingElse', 'b':12},
{'a': 'something', 'b':12},
{'a': 'somethingElse', 'b':12}]

最简单的方法是获取a的值为某物的元素的最后一个索引。在这种情况下3.是否有避免循环的方法...

What would be the most cleanest way to get the last index of the element where a has the value 'something'. In this case 3. Is there any way to avoid loops...

推荐答案

您可以使用 findIndex 获取索引。

You can use findIndex to get index. This will give you first index, so you will have to reverse the array.

var d = [{'a': "something", 'b':12}, {'a': "something", 'b':12}, {'a': "somethingElse", 'b':12}, {'a': "something", 'b':12}, {'a': "somethingElse", 'b':12}]

function findLastIndex(array, searchKey, searchValue) {
  var index = array.slice().reverse().findIndex(x => x[searchKey] === searchValue);
  var count = array.length - 1
  var finalIndex = index >= 0 ? count - index : index;
  console.log(finalIndex)
  return finalIndex;
}

findLastIndex(d, 'a', 'something')
findLastIndex(d, 'a', 'nothing')

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