你如何找到具有一定特征的数组中的第一个元素？ [英] How do you find the first element in array that has a certain characteristic?

问题描述

例如，如果您正在搜索处理零件的数组，并且尝试查找该数组中具有一定权重的第一个元素。像重量一样，在零件阵列中，第一个元件（部件）的重量为15，第二个元件（零件）的重量为10，则会返回该元件。这些是我使用的方法，我需要再做一个方法，我想我可能需要调用其中的一个。

 类Robot {
 Part [] parts; 
 public Robot（）{//未显示实现} 
 public void addPart（PArt p）{//未显示实现} 
} 
 
 class Part { 
 //类别细节未显示
 public double getWeight（）{
} 
 public int get Partnum（）{
 
} 
 public getMaterial（）{
 
} 
} 
  

解决方案

  double searchForLen = 10.00; （int i = 0; i< parts.length; i ++）{
 if（parts [i] .getWeight（）== searchForLen）{
 return parts [i] 
} 
} 
  

我会采取Brian的建议，并更改键入的重量。如果您坚持使用双重，您可以使用双重，然后调用Double.compare（）

For example if you are searching through an array that deals with parts and you are trying to find the first element in that array that has a certain weight. Like if the weight was 10 and in the parts array the first element(part) had a weight of 15 and the second element(part) had a weight of 10 it would return that element. These are the methods that I used.I need to make another method though and I think I might need to call one of these.

class Robot {
Part[] parts;
    public Robot () { // implementation is not shown }
    public void addPart(PArt p) { // implementation not shown }
}

class Part {
// Class details not shown
    public double getWeight() {
    }
    public int get Partnum() {

    }
    public getMaterial() {

    }
}

解决方案

double searchForLen = 10.00;
for (int i=0; i < parts.length; i++) {
  if (parts[i].getWeight() == searchForLen) {
    return parts[i];
  }
}

I would take Brian's advice and change the type of the weight. If you insist on staying with double you can use Double and then call Double.compare()

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