为什么以下代码不产生分段错误？ [英] Why doesn't the following code produce a segmentation fault?

问题描述

#include <iostream>
using namespace std;

int a[4];
int main(){
    int b=7;
    cout<<a[b]<<endl;
    return 0;
}

我试图访问未分配的内存。所以我希望输出是分段错误，而不是输出是一些垃圾值。

I was trying to access the memory that was not allocated. So I expect the output to be a segmentation fault,instead the output is some garbage value.

后来我将 b增加到1000，现在输出是细分错误。

Later I increased 'b' to 1000, now the output is 'Segmentation fault'. Is there a specific reason for this kind of behaviour?

我正在使用gcc-4.3.2编译器。

I'm using gcc-4.3.2 compiler.

推荐答案

分段错误如果您尝试访问不存在的内存地址（外部进程的地址空间），则可能会抛出该错误。

A segmentation fault may be thrown if you are attempting to access a nonexistent memory address (outside process's address space).

a [7] 在这种情况下可能不在其可访问空间之外，但 a [1000] 当然是。但是，即使您最不希望它，甚至前者也会爆炸；）

a[7] might not be outside its accessible space in this case but a[1000] most certainly is. But even the former will blow up, when you least expect it ;)

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